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4(1/2)^x-1=5x+2
We move all terms to the left:
4(1/2)^x-1-(5x+2)=0
Domain of the equation: 2)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4(+1/2)^x-(5x+2)-1=0
We get rid of parentheses
4(+1/2)^x-5x-2-1=0
We multiply all the terms by the denominator
4(+1-5x*2)^x-2*2)^x-1*2)^x=0
We add all the numbers together, and all the variables
4(-5x*2+1)^x-2*2)^x-1*2)^x=0
Wy multiply elements
-8x^2+4(-5x*2+1)^x=0
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